Possible Explanation Why τ_{B^{\pm}}\simτ_{B^0} But τ_{D^{\pm}}\sim τ_{D^0}

Physics – High Energy Physics – High Energy Physics - Phenomenology

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14 pages, latex, 4 ps figures. to appear in Phys. Rev. D

Scientific paper

10.1103/PhysRevD.57.6807

Data show that \tau_{B^{\pm}}\sim\tau_{B^0}, but \tau_{D^{\pm}}\sim 2\tau_{D^0}. The naive interpretation which attributes \tau_{D^{\pm}}\sim 2\tau_{D^0} to a destructive interference between two quark diagrams for D^{\pm} decays, definitely fails in the B-case. We investigate Close and Lipkin's suggestion that the phases for producing radially excited states \psi_{2s} in the decay products of B-mesons can possess an opposite sign to the integrals for \psi_{1s} decay products. Their contributions can partially compensate each other to result in \tau_{B^{\pm}}\sim\tau_{B^0}. Since D-mesons are much lighter than B-mesons, such possibilities do not exist in D-decays.

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