In a hot, chirally symmetric phase, $π^0$ doesn't go into $2 γ$, but $π^0 σ$ does

Details In a hot, chirally symmetric phase, $π^0$ doesn't go into $2 γ$, but $π^0 σ$ does In a hot, chirally symmetric phase, $π^0$ doesn't go into $2 γ$, but $π^0 σ$ does

1995-10-23

arxiv.org/abs/hep-ph/9510375v1

Physics

High Energy Physics

High Energy Physics - Phenomenology

7 pages, LaTeX. To appear in: "From thermal field theory to neural networks, a day to remember Tanguy Altherr", World Scientif

Scientific paper

In a constituent quark model at nonzero temperature, the amplitude for $\pi^0
\rightarrow 2 \gamma$ vanishes in a chirally symmetric phase, while that for
$\pi^0 \sigma \rightarrow 2 \gamma$ does not.

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