Orbital angular momentum is dependent on polarization

Physics – Optics

Scientific paper

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12 pages

Scientific paper

After presenting a new approach to separate the total angular momentum of an electromagnetic beam into the spin and orbital parts, which manifests that the spin angular momentum originates from that part of the linear momentum density the total amount of which is equal to zero, I show that the orbital angular momentum as well as the spin angular momentum of a non-paraxial monochromatic beam is dependent on the polarization ellipticity $\sigma$. The $\sigma$-dependent term of the orbital angular momentum is mediated by the recently advanced symmetry axis $\mathbf{I}$; and the transverse component of the orbital angular momentum is consistent with the transverse displacement of the beam's barycenter from the plane formed by $\mathbf{I}$ and the propagation axis. For a beam of angular-spectrum scalar amplitude $f(k_{\rho}, \varphi)= f_0 (k_{\rho}) \exp (il \varphi)$, the total angular momentum per unit energy in the propagation direction is simply $\frac{l+ \sigma}{\omega}$ for $\Theta= \frac{\pi}{2}$ and $\frac{l}{\omega}$ for $\Theta=0$, where $l$ is an integer, $\omega$ is the angular frequency, and $\Theta$ is the angle between $\mathbf{I}$ and the propagation axis.

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