Magnetic moments of the ground-state $\mathbf{J^P=(3/2)}^{+}$ baryon decuplet

Details Magnetic moments of the ground-state $\mathbf{J^P=(3/2)}^{+}$ baryon decuplet Magnetic moments of the ground-state $\mathbf{J^P=(3/2)}^{+}$ baryon decuplet

2011-07-13

arxiv.org/abs/1107.2838v2

Physics

High Energy Physics

High Energy Physics - Phenomenology

9 pages including 1 figure and 1 table. Corrected typos in Eqs.(7) and (8). Results and conclusions unchanged. arXiv admin not

Scientific paper

The magnetic moment - a function of the electric charge form factor $F_{1}(q^{2})$ and the magnetic dipole form factor $F_{2}(q^{2})$ at zero four-momentum transfer $q^{2}$-of the ground-state $J^{P}=(3/2)^{+}$ baryon decuplet magnetic moments have been studied for many years with limited success. At present, only the magnetic moment of the $\Omega^{-}$ has been accurately determined. We calculate nonperturbatively the magnetic moments of the \emph{physical baryon decuplet $J^{P}=(3/2)^{+}$} members and in particular, we obtain $\mu_{\Delta^{++}}= (+3.67 \pm 0.07) \mu_{N}$, $\mu_{\Delta^{+}}= (+1.83 \pm 0.04) \mu_{N}$, $\mu_{\Delta^{0}}= (0) \mu_{N}$, and the magnetic moments of their $U$-Spin partners in terms of $\Omega^{-}$ magnetic moment data.

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