Exactly massless quarks on the lattice

Physics – High Energy Physics – High Energy Physics - Lattice

Scientific paper

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7 pages, plain TeX; references corrected

Scientific paper

10.1016/S0370-2693(97)01368-3

It is suggested that the fermion determinant for a vector-like gauge theory with strictly massless quarks can be represented on the lattice as $\det{{1+V}\over 2}$, where $V=X(X^\dagger X)^{-1/2}$ and $X$ is the Wilson-Dirac lattice operator with a negative mass term. There is no undesired doubling and no need for any fine tuning. Several other appealing features of the formula are pointed out.

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