The Hilbert transform does not map L^1(Mw) to L^{1,\infty}(w)

Details The Hilbert transform does not map L^1(Mw) to L^{1,\infty}(w) The Hilbert transform does not map L^1(Mw) to L^{1,\infty}(w)

2010-11-08

arxiv.org/abs/1011.1767v1

Mathematics

Classical Analysis and ODEs

5 pages

Scientific paper

We prove that the analogue for the Hilbert transform of a classical weighted
inequality by Fefferman and Stein for the Hardy Littlewood maximal operator
does not hold. This is a sequel to paper arXiv:1008.3943 by the first author,
which shows the same for the general Haar multiplier operator.

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