Pfister's theorem fails in the free case

Details Pfister's theorem fails in the free case Pfister's theorem fails in the free case

2011-02-09

arxiv.org/abs/1102.1768v1

Mathematics

Rings and Algebras

Scientific paper

Artin solved Hilbert's $17^{th}$ problem by showing that every positive semidefinite polynomial can be realized as a sum of squares of rational functions. Pfister gave a bound on the number of squares of rational functions: if $p$ is a positive semi-definite polynomial in $n$ variables, then there is a polynomial $q$ so that $q^2p$ is a sum of at most $2^n$ squares. As shown by D'Angelo and Lebl, the analog of Pfister's theorem fails in the case of Hermitian polynomials. Specifically, it was shown that the rank of any multiple of the polynomial $\|z\|^{2d} \equiv (\sum_j |z_j|^2)^d$ is bounded below by a quantity depending on $d$. Here we prove that a similar result holds in a free $\ast$-algebra.

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