On the Eigenvalues of the Operator $(Tf)(t)=f(t)-\sum_{n=0}^\infty\frac{f^{(n)}(0)}{n!}t^n$

Details On the Eigenvalues of the Operator $(Tf)(t)=f(t)-\sum_{n=0}^\infty\frac{f^{(n)}(0)}{n!}t^n$ On the Eigenvalues of the Operator $(Tf)(t)=f(t)-\sum_{n=0}^\infty\frac{f^{(n)}(0)}{n!}t^n$

2011-05-13

arxiv.org/abs/1105.2613v2

Mathematics

General Mathematics

This paper has been withdrawn by the author due to a crucial sign error in equation 1 This paper has been withdrawn by the aut

Scientific paper

We show that the only eigenvalues of this operator are 0 and 1.

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