Fuglede-Putnam type theorems via the Aluthge transform

Details Fuglede-Putnam type theorems via the Aluthge transform Fuglede-Putnam type theorems via the Aluthge transform

2011-12-06

arxiv.org/abs/1112.1302v1

Mathematics

Functional Analysis

13 pages; to appear in Positivity

Scientific paper

Let $A=U|A|$ and $B=V|B|$ be the polar decompositions of $A\in \mathbb{B}(\mathscr{H}_1)$ and $B\in \mathbb{B}(\mathscr{H}_2)$ and let $Com(A,B)$ stand for the set of operators $X\in\mathbb{B}(\mathscr{H}_2,\mathscr{H}_1)$ such that $AX=XB$. A pair $(A,B)$ is said to have the FP-property if $Com(A,B)\subseteqCom(A^\ast,B^\ast)$. Let $\tilde{C}$ denote the Aluthge transform of a bounded linear operator $C$. We show that (i) if $A$ and $B$ are invertible and $(A,B)$ has the FP-property, then so is $(\tilde{A},\tilde{B})$; (ii) if $A$ and $B$ are invertible, the spectrums of both $U$ and $V$ are contained in some open semicircle and $(\tilde{A},\tilde{B})$ has the FP-property, then so is $(A,B)$; (iii) if $(A,B)$ has the FP-property, then $Com(A,B)\subseteqCom(\tilde{A},\tilde{B})$, moreover, if $A$ is invertible, then $Com(A,B)=Com(\tilde{A},\tilde{B})$. Finally, if $Re(U|A|^{1\over2})\geq a>0$ and $Re(V|B|^{1\over2})\geq a>0$ and $X$ is an operator such that $U^* X=XV$, then we prove that $\|\tilde{A}^* X-X\tilde{B}\|_p\geq 2a\|\,|B|^{1\over2}X-X|B|^{1\over2}\|_p$ for any $1 \leq p \leq \infty$.

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