Consistency of $f(R)=\sqrt{R^{2}-R_{0}^2}$ Gravity with the Cosmological Observations in Palatini Formalism

Details Consistency of $f(R)=\sqrt{R^{2}-R_{0}^2}$ Gravity with the Cosmological Observations in Palatini Formalism Consistency of $f(R)=\sqrt{R^{2}-R_{0}^2}$ Gravity with the Cosmological Observations in Palatini Formalism

2007-05-07

arxiv.org/abs/0705.0889v1

Phys.Rev.D76:044008,2007

Astronomy and Astrophysics

Astrophysics

12 pages, 7 figures

Scientific paper

10.1103/PhysRevD.76.044008

In this work we study the dynamics of universe in $f(R)=\sqrt{R^2-R_{0}^2}$ modified gravity with Palatini formalism. We use data from recent observations as Supernova Type Ia (SNIa) Gold sample and Supernova Legacy Survey (SNLS) data, size of baryonic acoustic peak from Sloan Digital Sky Survey (SDSS), the position of the acoustic peak from the CMB observations and large scale structure formation (LSS) from the 2dFGRS survey to put constraint on the parameters of the model. To check the consistency of this action, we compare the age of old cosmological objects with the age of universe. In the combined analysis with the all the observations, we find the parameters of model as $R_0=6.192_{-0.177}^{+0.167}\times H_0^2$ and $\Omega_m=0.278_{-0.278}^{+0.273}$.

Affiliated with

Also associated with

No associations

Rating

Consistency of $f(R)=\sqrt{R^{2}-R_{0}^2}$ Gravity with the Cosmological Observations in Palatini Formalism does not yet have a rating. At this time, there are no reviews or comments for this scientific paper.

If you have personal experience with Consistency of $f(R)=\sqrt{R^{2}-R_{0}^2}$ Gravity with the Cosmological Observations in Palatini Formalism, we encourage you to share that experience with our LandOfFree.com community. Your opinion is very important and Consistency of $f(R)=\sqrt{R^{2}-R_{0}^2}$ Gravity with the Cosmological Observations in Palatini Formalism will most certainly appreciate the feedback.

Rate now

Comments { 0 }

Profile ID: LFWR-SCP-O-598512