Admissible operators and ${\mathcal H}_{\infty}$ calculus

Details Admissible operators and ${\mathcal H}_{\infty}$ calculus Admissible operators and ${\mathcal H}_{\infty}$ calculus

2010-01-20

arxiv.org/abs/1001.3482v2

Mathematics

Functional Analysis

19 pages

Scientific paper

Given a Hilbert space and the generator $A$ of a strongly continuous, exponentially stable, semigroup on this Hilbert space. For any $g(-s) \in {\mathcal H}_{\infty}$ we show that there exists an infinite-time admissible output operator $g(A)$. If $g$ is rational, then this operator is bounded, and equals the "normal" definition of $g(A)$. In particular, when $g(s)=1/(s + \alpha)$, $ \alpha \in {\mathbb C}_0^+$, then this admissible output operator equals $(\alpha I - A)^{-1}$. Although in general $g(A)$ may be unbounded, we always have that $g(A)$ multiplied by the semigroup is a bounded operator for every (strictly) positive time instant. Furthermore, when there exists an admissible output operator $C$ such that $(C,A)$ is exactly observable, then $g(A)$ is bounded for all $g$'s with $g(-s) \in {\mathcal H}_{\infty}$, i.e., there exists a bounded ${\mathcal H}_{\infty}$-calculus. Moreover, we rediscover some well-known classes of generators also having a bounded ${\mathcal H}_{\infty}$-calculus.

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