Astronomy and Astrophysics – Astronomy
Scientific paper
Aug 1991
adsabs.harvard.edu/cgi-bin/nph-data_query?bibcode=1991stin...9218400r&link_type=abstract
Unknown
Astronomy and Astrophysics
Astronomy
Black Holes (Astronomy), Cosmology, Einstein Equations, Field Theory (Physics), Gravitation, Gravitational Fields, Hadrons, Regge Poles, Angular Momentum, Schwarzschild Metric
Scientific paper
Within a purely classical formulation of 'strong gravity', we associated hadron constituents (and even hadrons themselves) with suitable stationary, axisymmetric solutions of certain new Einstein-type equations supposed to describe the strong field inside hadrons. Such equations are nothing but Einstein equations - with cosmological term - suitably scaled down. As a consequence, the cosmological constant (lambda) and the masses M result in our theory to be scaled up and transformed into a 'hadronic constant' and into 'strong masses', respectively. Due to the unusual range of lambda and M values considered, we met a series of solutions of the Kerr-Newman-de Sitter (KNdS) type with such interesting properties that it is worth studying them - from our particular point of view - also in the case of ordinary gravity. This is the aim of the present work. The requirement that those solutions be stable, i.e., that their temperature (or surface gravity) be vanishingly small, implies the coincidence of at least two of their (in general, three) horizons. Imposing the stability condition of a certain horizon does yield (once chosen the values of J, q, and lambda) mass and radius of the associated black-hole. In the case of ordinary Einstein equations and for stable black-holes of the KNdS type, we get in particular Regge-like relations among mass M, angular momentum J, charge q, and cosmological constant (lambda). For instance, with the standard definitions Q2 is identical to Gq2 /(4(pi)(epsilon)0c4); a is identical to J/(Mc); m is identical to GM/c2, in the case lambda = 0 in which m2 = a2 + Q2 and if q is negligible we find m2 = J. When considering, for simplicity, lambda greater than 0 and J = 0 (and q still negligible), then we obtain m2 = 1/(9(lambda)).
Recami Erasmo
Tonin-Zanchin Vilson
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