A fancy way to obtain the binary digits of $759250125\sqrt{2}$

Details A fancy way to obtain the binary digits of $759250125\sqrt{2}$ A fancy way to obtain the binary digits of $759250125\sqrt{2}$

2009-02-24

arxiv.org/abs/0902.4168v2

Mathematics

Number Theory

7 pages, 2 figure

Scientific paper

R. L. Graham and H. O. Pollak observed that the sequence $$u_1=1,\qquad u_{n+1}=\lfloor \sqrt{2} (u_n+1/2)\rfloor, \quad n\geq 1,$$ has the curious property that the sequence of numbers $(u_{2n+1}-2u_{2n-1})_{n\geq 1}$ denotes the binary digits of $\sqrt{2}$. We present an extension of Graham--Pollak's sequence which allows to get -- in a fancy way -- the binary digits of $759250125\sqrt{2}$ and other numbers.

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