A comparison between the max and min norms on $C^*(F_n) \otimes C^*(F_n)$

Details A comparison between the max and min norms on $C^*(F_n) \otimes C^*(F_n)$ A comparison between the max and min norms on $C^*(F_n) \otimes C^*(F_n)$

2002-02-07

arxiv.org/abs/math/0202061v1

Mathematics

Operator Algebras

11 pages, AMS-LaTeX

Scientific paper

Let $F_n$, $n\geq2$, be the free group with $n$ generators, denoted by $U_1,U_2,...,U_n$. Let $C*(F_n)$ be the full $C^*$-algebra of $F_n$. Let $\mathcal{X}$ be the vector subspace of the algebraic tensor product $C^*(F_n) \otimes C^*(F_n)$, spanned by $1\otimes1,U_1\otimes1,...,U_n\otimes1,1\otimes U_1,...,1\otimes U_n$. Let $|| \cdot ||_{\min}$ and $|| \cdot ||_{\max}$ be the minimal and maximal $C^*$ tensor norms on $C^*(F_n) \otimes C^*(F_n)$, and use the same notation for the corresponding (matrix) norms induced on $M_k(\mathbb{C})\otimes\mathcal{X}$. Identifying $\mathcal{X}$ with the subspace of $C^*(F_{2n})$ obtained by mapping $U_1\otimes1,...,1\otimes U_n$ into the $2n$ generators and the identity into the identity, we get a matrix norm $|| \cdot ||_{C^*(F_{2n})}$ which dominates the $|| \cdot ||_{\max}$ norm, on $M_k(\mathbb{C})\otimes\mathcal{X}$. In this paper we prove that, with $N=2n+1=\dim\mathcal{X}$, we have $||X||_{\max} \leq ||X||_{C^*(F_{2n})} \leq (N^2-N)^{1/2} ||X||_{\min}, X\in M_k(\mathbb{C})\otimes\mathcal{X}$.

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