New separation between $s(f)$ and $bs(f)$

Details New separation between $s(f)$ and $bs(f)$ New separation between $s(f)$ and $bs(f)$

2011-08-17

arxiv.org/abs/1108.3494v1

Computer Science

Computational Complexity

7 pages

Scientific paper

In this note we give a new separation between sensitivity and block
sensitivity of Boolean functions: $bs(f)=(2/3)s(f)^2-(1/3)s(f)$.

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