On CH + 2^{aleph_1}-> (alpha)^2_2 for alpha < omega_2

Mathematics – Logic

Scientific paper

Rate now

  [ 0.00 ] – not rated yet Voters 0   Comments 0

Details

Scientific paper

We prove the consistency of ``CH + 2^{aleph_1} is arbitrarily large +
2^{aleph_1} not-> (omega_1 x omega)^2_2''. If fact, we can get 2^{aleph_1}
not-> [omega_1 x omega]^2_{aleph_0}. In addition to this theorem, we give
generalizations to other cardinals.

No associations

LandOfFree

Say what you really think

Search LandOfFree.com for scientists and scientific papers. Rate them and share your experience with other people.

Rating

On CH + 2^{aleph_1}-> (alpha)^2_2 for alpha < omega_2 does not yet have a rating. At this time, there are no reviews or comments for this scientific paper.

If you have personal experience with On CH + 2^{aleph_1}-> (alpha)^2_2 for alpha < omega_2, we encourage you to share that experience with our LandOfFree.com community. Your opinion is very important and On CH + 2^{aleph_1}-> (alpha)^2_2 for alpha < omega_2 will most certainly appreciate the feedback.

Rate now

     

Profile ID: LFWR-SCP-O-228633

  Search
All data on this website is collected from public sources. Our data reflects the most accurate information available at the time of publication.